Real-life: delayWhen() a deferred notification

Delay the notification with delayWhen and timer(0).

1. Solve the task in the editor — no long theory.
2. Run the check and compare your output with the expected result.
3. Stuck? Open the solution and carry the approach into your own code.

const { of, timer, delayWhen } = Rx;

const result$ = of('notify').pipe(
  delayWhen(() => timer(0))
);

result$.subscribe(value => console.log(value));